Spin Operator - Relative to Velocity: SPEED Value Question
#3
Thanks for the reply Tyson. Good to know. Looking at the code it seems that there is no "maxing out" once it reaches the threshold? It's instead just a simple multiplier, right?
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RE: Spin Operator - Relative to Velocity: SPEED Value Question - by mitchfx - 03-14-2021, 12:48 PM

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